Problem:
Creating new IP addresses composed of the first three original segments coupled with the last original segment multiplied by two.
Solution:
Use the LEFT, FIND, and MID functions as shown in the following formula:
=(LEFT(A2,FIND(".",A2,FIND(".",A2,FIND(".",A2)+1)+1)))&(MID(A2,
FIND(".",A2,FIND(".",A2,FIND(".",A2)+1)+1)+1,99)*2)
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hotpepper wrote on May 17, 2005 01:23 EST |
This tip shows up with double quotes instead of single quotes.
I think it should read like this:
=(LEFT(A2,FIND(".",A2,FIND(".",A2,FIND(".",A2)+1)+1)))&(MID(A2,FIND(".",A2,FIND(".",A2,FIND(".",A2)+1)+1)+1,99)*2)
Another thought on this problem:
=REPLACE(A2,FIND("~",SUBSTITUTE(A2,".","~",3)),99,"." &MID(A2,FIND("~",SUBSTITUTE(A2,".","~",3))+1,99)*2) |
One fault
excel newbee wrote on December 31, 1969 19:00 EST |
| Can we make formula to take care of constraints on the IP address? ... checking for values greater than 256 et al. |
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