Problem:
List1 (column A) contains 10 numbers, two of which (0 & 500) are significantly smaller or greater than the remainder.
If included in an average calculation, these exceptional values would disproportionately influence the result.
We, therefore, need a way of calculating an average that more accurately reflects the general spread of data.
Solution:
Use the TRIMMEAN function as shown in the following formula:
=TRIMMEAN(A2:A11,0.2)
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